Answer of this children’s day special puzzle is – 10
To solve the equation lets assume equations are as follows
A + B = 10 => First Equation
B – C = 20 => Second Equation
C + A = ?? => Third Equation
If you subtract the second equation from first we will get
(A + B) – (B – C) = 10 – 20
A + B – B + C = -10
A + C = -10
So the answer is – 10
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